So, I have this stuff called Lugol’s Iodine solution, 2% - and I don’t know how to figure out the exact measurements of the chemicals. The website says this…
Calculating Number of MG’s of Iodine and Potassium Iodide per Drop of Lugol’s Solution:
LUGOL’S 5%: Each VERTICAL drop is about 6.25 mg’s of iodine/potassium iodide (2.5 mg iodine, 3.75 mg potassium iodide) and 2 drops is about 12.50 mg’s of iodine/potassium iodide (5.0 mg iodine, 7.50 mg potassium iodide). Compared to other’s, J.CROW’S® Lugol’s Solution offers big savings.
LUGOL’S 2%: Slightly less than 1/2 half the above measurements.
It’s maddeningly unscientific, I know. “about” and “slightly less” - it’s not an ideal product, but it’s one that I already have. I have most of a bottle left and since my recipe has gotten pretty expensive, I would like to use this until it’s gone before I buy something better. Can anyone help me figure out approximately how much iodine/potassium would be contained in one drop of the 2% solution?
Any help would be appreciated.